Section 1.9 Question 18 Let cr = cube root f(g(x)) = (cr{x - 5})^3 + 5 f(g(x)) = x - 5 + 5 f(g(x)) = x Let cr = cube root g(f(x)) = cr{x^3 + 5 - 5} g(f(x)) = cr{x^3} g(f(x)) = x Since f(g(x)) = g(f(x)), f and g are inverse functions. [ATTACH=full]262[/ATTACH]