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Section 1.9
Question 18
Let cr = cube root
f(g(x)) = (cr{x - 5})^3 + 5
f(g(x)) = x - 5 + 5
f(g(x)) = x
Let cr = cube root
g(f(x)) = cr{x^3 + 5 - 5}
g(f(x)) = cr{x^3}
g(f(x)) = x
Since f(g(x)) = g(f(x)), f and g are inverse functions.
Question 18
Let cr = cube root
f(g(x)) = (cr{x - 5})^3 + 5
f(g(x)) = x - 5 + 5
f(g(x)) = x
Let cr = cube root
g(f(x)) = cr{x^3 + 5 - 5}
g(f(x)) = cr{x^3}
g(f(x)) = x
Since f(g(x)) = g(f(x)), f and g are inverse functions.