Using the Value of A Function...2

Discussion in 'Geometry and Trigonometry' started by nycmathguy, Oct 30, 2021.

  1. nycmathguy

    nycmathguy

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    Section 4.2

    20211029_191711.jpg

    20211029_191257.jpg
     
    nycmathguy, Oct 30, 2021
    #1
  2. nycmathguy

    MathLover1

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    [​IMG] => false
    correct is:
    [​IMG] and also [​IMG]
     
    MathLover1, Oct 30, 2021
    #2
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  3. nycmathguy

    nycmathguy

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    cos(pi - t) = - cost =

    -cos(t) = 4/5

    Now solve for t. Yes?
     
    nycmathguy, Oct 30, 2021
    #3
  4. nycmathguy

    MathLover1

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    Yes
     
    MathLover1, Oct 30, 2021
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  5. nycmathguy

    nycmathguy

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    Ok. Cool.
     
    nycmathguy, Oct 30, 2021
    #5
  6. nycmathguy

    nycmathguy

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    20211030_121958.jpg
     
    nycmathguy, Oct 30, 2021
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  7. nycmathguy

    MathLover1

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    perfect
     
    MathLover1, Oct 30, 2021
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  8. nycmathguy

    nycmathguy

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    Thanks. No beach today. Too cold to walk on the boardwalk.
     
    nycmathguy, Oct 30, 2021
    #8
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