Traveling By Jet

Discussion in 'Geometry and Trigonometry' started by nycmathguy, Dec 5, 2021.

  1. nycmathguy

    nycmathguy

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    Section 4.8

    1. Am I right or wrong?

    2. Is my drawing wrong? If so, please draw the correct geometric figure.

    Thank you.
    Screenshot_20211204-191443_Samsung Notes.jpg

    IMG_20211205_131255.jpg
     
    nycmathguy, Dec 5, 2021
    #1
  2. nycmathguy

    MathLover1

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    A compass bearing of 100° (E by S) is 10° south of 90°.

    The jet is flying the hypotenuse of a right triangle.
    upload_2021-12-5_12-41-7.jpeg
    (a) Distances from Miami

    sin(10) = OM/2472

    OM = 2472sin10 = 2472 × 0.173 648 = 429.26 mi

    OR = 2472cos10 = 2472 ×0.984 8077 = 2434.44 mi

    Reno is 2434.44 mi west and 429.26 mi north of Miami



    (b) Return bearing
    upload_2021-12-5_12-41-42.jpeg
    Bearing = 100 + 180 = 280°

    For the return flight, the jet should fly a bearing of 280° (W by N).
     
    MathLover1, Dec 5, 2021
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    nycmathguy likes this.
  3. nycmathguy

    nycmathguy

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    I got part (a) right using the wrong drawing. Crazy, right?

    Thanks for part (b).
     
    nycmathguy, Dec 5, 2021
    #3
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