Summation of 1/(k(k+1)) = 7/8

[Andrew08]

Help me solve that, please
I can't think of anything, except doing it manually which would probably take ages
The summation properties aren't helping me here

 

[MathLover1]

sum_(k=1)^n 1/(k(k+1)) =7/8

Result


n/(n + 1) = 7/8

Solution

n=7

 

[MathLover1]

sum_(k=1)^n 1/(k(k+1)) =7/8

Result


n/(n + 1) = 7/8

Solution

n=7

 

[Andrew08]

Result

Solution

I love you.

don't mind if I ask.. why is it equal to n/(n+1) ? how do I get there?

 

[MathLover1]

n=7

 

[nycmathguy]

n=7

Impressed. You know summation math as well. Very cool.

 

[MathLover1]

I love you.

don't mind if I ask.. why is it equal to n/(n+1) ? how do I get there?

sorry for not answering your question in details, it was way past midnight

you are given to find partial sum of the sequence with n terms, given that k=1 ->k=n

or k=1,2,3,....,n

you use general term 1/(k(k+1) , add n times

n(1/(k(k+1)).......now we substitute k, one with 1, second with n

n(1/(1(n+1)). ...simplify

n/(n+1)

 

[nycmathguy]

sorry for not answering your question in details, it was way past midnight

you are given to find partial sum of the sequence with n terms, given that k=1 ->k=n

or k=1,2,3,....,n

you use general term 1/(k(k+1) , add n times

n(1/(k(k+1)).......now we substitute k, one with 1, second with n

n(1/(1(n+1)). ...simplify

n/(n+1)

There's a section on summation in both precalculus textbooks. I look forward to your help in this regard.
Still a long way before we get there.

 

[Andrew08]

sorry for not answering your question in details, it was way past midnight

you are given to find partial sum of the sequence with n terms, given that k=1 ->k=n

or k=1,2,3,....,n

you use general term 1/(k(k+1) , add n times

n(1/(k(k+1)).......now we substitute k, one with 1, second with n

n(1/(1(n+1)). ...simplify

n/(n+1)

thank you very much!
do you have any pdf books where I can practice that? any recommendations?

 

[MathLover1]

what book do you prefer? I need to know what math course you are taking right now

 

[Andrew08]

what book do you prefer? I need to know what math course you are taking right now

a pre-calculus would probably be fine, I'm preparing for a high school level exam

 

[MathLover1]

what grade you are in right now?

 

[Andrew08]

what grade you are in right now?

I finished high school already

 

[MathLover1]

then a pre-calculus or calculus I would be fine

here are some suggestions regarding pdf books:

https://cec-code-lab.aps.edu/downloads/precalculus-text.pdf

https://www.stitz-zeager.com/szprecalculus07042013.pdf

 

[Andrew08]

then a pre-calculus or calculus I would be fine

here are some suggestions regarding pdf books:

https://cec-code-lab.aps.edu/downloads/precalculus-text.pdf

https://www.stitz-zeager.com/szprecalculus07042013.pdf

Thank you very much!! <3

 

[MathLover1]

are you in college right now?

 

[MathLover1]

here is good link for you, it's free

https://www.numerade.com/books/chapter/systems-of-equations-5/

 

[nycmathguy]

here is good link for you, it's free

https://www.numerade.com/books/chapter/systems-of-equations-5/

I like the link, too. I'll check it out.

 

[Andrew08]

are you in college right now?

yes, kinda! I took a break from college in order to prepare for that upcoming exam