Simplify Trigonometric Expressions...4

Discussion in 'Geometry and Trigonometry' started by nycmathguy, Dec 8, 2021.

  1. nycmathguy

    nycmathguy

    Joined:
    Jun 27, 2021
    Messages:
    5,386
    Likes Received:
    422
    Section 5.1

    Question 22

    sin^2 x•sec^2 x - sin^2 x

    sin^2 x(sec^2 x - 1)

    I know that sec^2 x - 1 = tan^2 x.

    sin^2 x(tan^2 x)

    sin^2 x (sin^2 x/cos^2 x)

    sin^4 x/cos^2 x

    Is this right?
     
    nycmathguy, Dec 8, 2021
    #1
  2. nycmathguy

    MathLover1

    Joined:
    Jun 27, 2021
    Messages:
    2,989
    Likes Received:
    2,884
    correct

    just simplify
    sin^4 (x)/cos^2( x)=sin^2(x)*tan^2(x)
     
    MathLover1, Dec 8, 2021
    #2
    nycmathguy likes this.
  3. nycmathguy

    nycmathguy

    Joined:
    Jun 27, 2021
    Messages:
    5,386
    Likes Received:
    422
    I don't understand the simplification.

    How does sin^4 (x)/cos^2( x)= sin^2(x)*tan^2(x)?
     
    nycmathguy, Dec 8, 2021
    #3
  4. nycmathguy

    MathLover1

    Joined:
    Jun 27, 2021
    Messages:
    2,989
    Likes Received:
    2,884
    sin^4 (x)=sin^2 (x)*sin^2 (x)

    then you have

    [​IMG] which is

    [​IMG]


    = sin^2(x)*tan^2(x)
     
    MathLover1, Dec 8, 2021
    #4
    nycmathguy likes this.
  5. nycmathguy

    nycmathguy

    Joined:
    Jun 27, 2021
    Messages:
    5,386
    Likes Received:
    422
    When you break it down piece by piece, it all makes sense.
     
    nycmathguy, Dec 9, 2021
    #5
Ask a Question

Want to reply to this thread or ask your own question?

You'll need to choose a username for the site, which only take a couple of moments (here). After that, you can post your question and our members will help you out.