Show that x -> x^p is an automorphism in K

Discussion in 'Linear and Abstract Algebra' started by filkoge, Dec 25, 2024 at 12:16 PM.

  1. filkoge

    filkoge

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    Let K be a finite field of characteristic p > 0. Show that s(x) = x^p is an automorphism in K.

    It is clear in case K is a prime field, because then s(x) is just an identity. If K is not prime, s(x) is identity on its prime subfield. But how to show the automorphism of s() for the rest of the field, when it's not prime?
     
    filkoge, Dec 25, 2024 at 12:16 PM
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