- Joined
- Jun 27, 2021
- Messages
- 5,386
- Reaction score
- 422
Section 2.1
Question 16
g(x) = x^2 + 2x +1
Note: I WILL NOT GRAPH g(x).
Express g(x) in standard form.
Factor g(x).
g(x) = (x + 1)(x + 1)
g(x) = (x + 1)^2 + 0
Find vertex (h, k).
Let h = -1.
Let k = 0
From the standard form, the vertex is clearly the point (-1, 0).
I now need the axis of symmetry.
The x-coordinate of the vertex is the axis of symmetry. So, it is x = -1.
To find the x-intercepts, set g(x) to 0 and solve for x.
Let g(x) = 0.
0 = (x + 1)^2 + 0
0 = (x + 1)^2
sqrt{0} = sqrt{(x + 1)^2}
0 = x + 1
- 1 = x
The only x-intercept occurs at the point (-1, 0).
You say?
Question 16
g(x) = x^2 + 2x +1
Note: I WILL NOT GRAPH g(x).
Express g(x) in standard form.
Factor g(x).
g(x) = (x + 1)(x + 1)
g(x) = (x + 1)^2 + 0
Find vertex (h, k).
Let h = -1.
Let k = 0
From the standard form, the vertex is clearly the point (-1, 0).
I now need the axis of symmetry.
The x-coordinate of the vertex is the axis of symmetry. So, it is x = -1.
To find the x-intercepts, set g(x) to 0 and solve for x.
Let g(x) = 0.
0 = (x + 1)^2 + 0
0 = (x + 1)^2
sqrt{0} = sqrt{(x + 1)^2}
0 = x + 1
- 1 = x
The only x-intercept occurs at the point (-1, 0).
You say?
