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Section 3.146 & 48[ATTACH=full]638[/ATTACH]Question 46e^(2x - 1) = e^4The base e is the same on both sides.2x - 1 = 42x = 4 + 12x = 5x = 5/2Question 48e^(x^2 + 6) = e^5xx^2 + 6 = 5xx^2 - 5x + 6 = 0(x - 3)(x - 2) = 0x - 3 = 0x = 3x - 2 = 0x = 2NOTE: We will continue with precalculus this week and back to calculus 1 next week.
Section 3.1
46 & 48
[ATTACH=full]638[/ATTACH]
Question 46
e^(2x - 1) = e^4
The base e is the same on both sides.
2x - 1 = 4
2x = 4 + 1
2x = 5
x = 5/2
Question 48
e^(x^2 + 6) = e^5x
x^2 + 6 = 5x
x^2 - 5x + 6 = 0
(x - 3)(x - 2) = 0
x - 3 = 0
x = 3
x - 2 = 0
x = 2
NOTE: We will continue with precalculus this week and back to calculus 1 next week.
