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A certain pet store sells only dogs and cats. In March, the store sold twice as many dogs as cats. In April, the store sold twice the number of dogs that it sold in March, and three times the number of cats that it sold in March. If the total number of pets the store sold in March and April combined was 500, how many dogs did the store sell in March?
(A) 80
(B) 100
(C) 120
(D) 160
(E) 180
Let me see.
Twice as many dogs as cats in March:
Dogs = 2x
Cats = x
In April, twice as many dogs as it sold in March:
Dogs = 2(2x)
Three times the number of cats it sold in March:
Cats = 3x
Total number of pets sold = 500.
Here is my equation:
2(2x) + 3x = 500
Solving for x leads to a decimal answer, which is wrong.
Stuck here....
Someone suggested following equation:
2(March) + March + 3(March) + March = 500
This leads to the following equation:
2(2x) + 2x + 3x + x = 500
If the suggestion is correct, why add March and April?
(A) 80
(B) 100
(C) 120
(D) 160
(E) 180
Let me see.
Twice as many dogs as cats in March:
Dogs = 2x
Cats = x
In April, twice as many dogs as it sold in March:
Dogs = 2(2x)
Three times the number of cats it sold in March:
Cats = 3x
Total number of pets sold = 500.
Here is my equation:
2(2x) + 3x = 500
Solving for x leads to a decimal answer, which is wrong.
Stuck here....
Someone suggested following equation:
2(March) + March + 3(March) + March = 500
This leads to the following equation:
2(2x) + 2x + 3x + x = 500
If the suggestion is correct, why add March and April?
Last edited: