Mixture...2

Discussion in 'Algebra' started by nycmathguy, Feb 9, 2022.

  1. nycmathguy

    nycmathguy

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    A store owner wants to mix cashews and almonds. Cashews cost 2 dollars per pound and almonds cost 5 dollars per pound. He plans to sell 150 pounds of a mixture. How many pounds of each type of nuts should be mixed if the mixture will cost 3 dollars?

    I can set up two equations in two unknowns but there is a "mixture way" to solve this problem involving only one variable.

    Let p = pounds

    2p = cashews

    5p = almonds

    Stuck....
     
    nycmathguy, Feb 9, 2022
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  2. nycmathguy

    MathLover1

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    Let x be the number of pounds of cashews.

    So, 150 - x will represent the number of almonds.

    Since each pound of the mixture costs 3 dollars, 150 pounds will cost 3 × 150 = 450 dollars.

    Cost of cashews + cost of almonds = 450

    2 × x + (150 - x) × 5 = 450

    2x + 150 × 5 - x × 5 = 450

    2x + 750 - 5x = 450

    2x - 5x + 750 = 450

    -3x + 750 = 450

    -3x + 750 - 750 = 450 - 750

    -3x = -300

    -3x/-3 = -300/-3

    x = 100

    150 - x = 150 - 100 = 50.

    The store owner should mix 100 pounds of cashews with 50 pounds of almonds.
     
    MathLover1, Feb 10, 2022
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    nycmathguy likes this.
  3. nycmathguy

    nycmathguy

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    I think the time has come for me to realize that it is not possible to understand every math topic. Word problems will forever be foreign to me.
     
    nycmathguy, Feb 10, 2022
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