Leading Coefficient Test...1

Discussion in 'Other Pre-University Math' started by nycmathguy, Aug 28, 2021.

  1. nycmathguy

    nycmathguy

    Joined:
    Jun 27, 2021
    Messages:
    5,386
    Likes Received:
    422
    Section 2.2
    Question 20

    Can you solve 20 as a guide for me to do a few more? What is the Leading Coefficient Test for anyway?

    20210827_202945.jpg
     
    nycmathguy, Aug 28, 2021
    #1
  2. nycmathguy

    MathLover1

    Joined:
    Jun 27, 2021
    Messages:
    2,989
    Likes Received:
    2,884
    The leading coefficient test tells us that the graph rises or falls depending on whether the leading terms are positive or negative, so for left-hand behavior (negative numbers), you will need to look at both the coefficient and the degree of the component together.

    Let’s look at the following examples of when x is negative:

    Leading coefficient test:

    2x^3would be a positive coefficient multiplied by a negative variable=>it is negative
    2x^4 would be a positive coefficient multiplied by a positive variable=>it is positive
    -5x^3 would be a negative coefficient multiplied by a negative variable=>it is positive
    -5x^2 would be a negative coefficient multiplied by a positive variable=>it is negative

    same procedure for right-hand behavior (positive numbers)

    20.
    f(x)= 2x^2-3x+1

    left-hand behavior (negative numbers),

    2x^2 would be a positive coefficient multiplied by a positive variable=>it is positive
    right-hand behavior (positive numbers)

    the coefficient and the degree of the component together greater than zero=>the graph rises

    2x^2 would be a positive coefficient multiplied by a positive variable=>it is positive
    the coefficient and the degree of the component together greater than zero=>the graph rises

    [​IMG] as you can see, from the turning point (vertex) the graph goes up on both sides (left and right)


     
    MathLover1, Aug 28, 2021
    #2
    nycmathguy likes this.
  3. nycmathguy

    nycmathguy

    Joined:
    Jun 27, 2021
    Messages:
    5,386
    Likes Received:
    422
    You said:

    Leading coefficient test:

    2x^3would be a positive coefficient multiplied by a negative variable=>it is negative
    2x^4 would be a positive coefficient multiplied by a positive variable=>it is positive
    -5x^3 would be a negative coefficient multiplied by a negative variable=>it is positive
    -5x^2 would be a negative coefficient multiplied by a positive variable=>it is negative

    same procedure for right-hand behavior (positive numbers)

    1. Can you provide a list for the right-hand behavior?

    You said:

    ". . .the coefficient and the degree of the component together greater than zero=>the graph rises."

    2. What do you mean by the coefficient and the degree of the component together greater 0?
     
    nycmathguy, Aug 28, 2021
    #3
  4. nycmathguy

    MathLover1

    Joined:
    Jun 27, 2021
    Messages:
    2,989
    Likes Received:
    2,884
    left-hand behavior (negative numbers),

    2x^2 would be a positive coefficient multiplied by a positive variable=>it is positive

    2x^2 =>the coefficient is 2 (means positive number greater 0)
    if x=-1=> then x^2=(-1)^2=1 (means positive number greater 0)
    so, combined 2x^2=(-1)^2=2*1=2 (means positive number greater 0) and y value goes up, so the graph rises


    right-hand behavior (positive numbers)
    the coefficient and the degree of the component together greater than zero=>the graph rises and approaching infinity

    2x^2 =>the coefficient is 2 (means positive number greater 0)
    if x=1=> then x^2=1^2=1 (means positive number greater 0)
    so, combined 2x^2=2^1^2=2*1=2 (means positive number greater 0) and y value goes up,
    so the graph rises and approaching infinity

    imagine you drawing this parabola starting at vertex, the curve goes from vertex up from both sides

    This graph is a second degree polynomial (i.e. the highest power of x is 2). Since 2 is even, the end behavior will be the same for the left and the right. The leading coefficient (the number in front of the highest power of x - which in this case is 2) is positive. This means both the left and right hand behavior will be approaching infinity. In proper mathematical speak - you could say that: as x approaches positive infinity, f(x) approaches positive infinity and as x approaches negative infinity, f(x) also approaches positive infinity.

     
    Last edited: Aug 28, 2021
    MathLover1, Aug 28, 2021
    #4
    nycmathguy likes this.
  5. nycmathguy

    nycmathguy

    Joined:
    Jun 27, 2021
    Messages:
    5,386
    Likes Received:
    422
    Wouldn't it be easier just to graph the function? From the graph itself, we can see the rise and fall.
     
    nycmathguy, Aug 28, 2021
    #5
  6. nycmathguy

    nycmathguy

    Joined:
    Jun 27, 2021
    Messages:
    5,386
    Likes Received:
    422
    You said:

    (20)= 2x^2-3x+1

    left-hand behavior (negative numbers)...

    1. What made you say left-hand behavior from simply looking at the given function?

    2. Is there another way to tackle questions such as this one?
     
    nycmathguy, Aug 28, 2021
    #6
  7. nycmathguy

    nycmathguy

    Joined:
    Jun 27, 2021
    Messages:
    5,386
    Likes Received:
    422
    Can we determine the left-hand and right-hand behavior of a graph using the number line?
     
    nycmathguy, Aug 28, 2021
    #7
  8. nycmathguy

    MathLover1

    Joined:
    Jun 27, 2021
    Messages:
    2,989
    Likes Received:
    2,884
    no
     
    MathLover1, Aug 28, 2021
    #8
  9. nycmathguy

    MathLover1

    Joined:
    Jun 27, 2021
    Messages:
    2,989
    Likes Received:
    2,884
    simply looking at the graph of the given function you can see what is happening if x->infinity or if x-> -infinity

    in this case you can see if x-> + infinity that f(x) ->+ infinity too
    and if x-> -infinity that f(x) -> +infinity

    + infinity means right side limit
    - infinity means left side limit

    here is good example:
     
    MathLover1, Aug 28, 2021
    #9
    nycmathguy likes this.
  10. nycmathguy

    nycmathguy

    Joined:
    Jun 27, 2021
    Messages:
    5,386
    Likes Received:
    422
    Thanks for video clip. I may need to use video lessons to learn most of the topics in Section 2.2. I will not post new questions until further notice. Feeling a bit frustrated in this section thus far.
     
    nycmathguy, Aug 28, 2021
    #10
  11. nycmathguy

    MathLover1

    Joined:
    Jun 27, 2021
    Messages:
    2,989
    Likes Received:
    2,884
    here are some videos for you:







     
    MathLover1, Aug 28, 2021
    #11
    nycmathguy likes this.
  12. nycmathguy

    nycmathguy

    Joined:
    Jun 27, 2021
    Messages:
    5,386
    Likes Received:
    422
    Thanks. I will view each video tomorrow.
     
    nycmathguy, Aug 29, 2021
    #12
Ask a Question

Want to reply to this thread or ask your own question?

You'll need to choose a username for the site, which only take a couple of moments (here). After that, you can post your question and our members will help you out.
Similar Threads
There are no similar threads yet.
Loading...