David Cohen Just do part (a). I will parts (b & c). [ATTACH=full]1866[/ATTACH]
Let me see. Part (b) For the little triangle above we use cosine. cos(theta) = 4/AB AB•cos(theta) = 4 AB = 4/cos(theta) Part (c) Here we use the sine function. From A to the right angle inside the little triangle, I will call that distance x. From that right angle to the one directly beneath, the distance is 5. sin(theta) = (x + 5)/(AB + BC) Note AB + BC = AC. sin(theta) = (x + 5)/AC AC•sin(theta) = (x + 5) AC = (x + 5)/sin(theta) Yes?