Determining Variation...2

Joined
Jun 27, 2021
Messages
5,386
Reaction score
422
Section 1.10
36 & 38

Question 36

y = kx

2 = 5k

2/5 = k

4 = 10k

4/10 = k

2/5 = k

I will stop here and assume that the form is y = kx.

The model that relates x and y is y = (2/5)k.

Question 38

y = kx

24 = 5k

24/5 = k

12 = 10k

12/10 = k

6/5 = k

Two distinct k values tells me that the form needed is y = k/x.

I will go back to the point (5, 24).

24 = k/5

24(5) = k

120 = k

Now use (10, 12).

12 = k/10

12(10) = k

120 = k

I can stop here and assume that the needed form is y = k/x.

The model that relates x and y is y = 120/x.

You say?



20210818_034420.jpg
 
Less is more means if you have less questions , you will have more time to go over answers, and you will understand theory better.
Understand theory better will lead to less time spent on answering questions, more capability of doing mental math and shortening steps to solutions.
 
Less is more means if you have less questions , you will have more time to go over answers, and you will understand theory better.
Understand theory better will lead to less time spent on answering questions, more capability of doing mental math and shortening steps to solutions.

I concur. Less time allows me to take my time learning theory. Theory is the key to understanding math and physics.
 

Members online

No members online now.

Forum statistics

Threads
2,523
Messages
9,840
Members
695
Latest member
LWM
Back
Top