Section 1.10 36 & 38 Question 36 y = kx 2 = 5k 2/5 = k 4 = 10k 4/10 = k 2/5 = k I will stop here and assume that the form is y = kx. The model that relates x and y is y = (2/5)k. Question 38 y = kx 24 = 5k 24/5 = k 12 = 10k 12/10 = k 6/5 = k Two distinct k values tells me that the form needed is y = k/x. I will go back to the point (5, 24). 24 = k/5 24(5) = k 120 = k Now use (10, 12). 12 = k/10 12(10) = k 120 = k I can stop here and assume that the needed form is y = k/x. The model that relates x and y is y = 120/x. You say? [ATTACH=full]277[/ATTACH]