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Section 1.10
36 & 38
Question 36
y = kx
2 = 5k
2/5 = k
4 = 10k
4/10 = k
2/5 = k
I will stop here and assume that the form is y = kx.
The model that relates x and y is y = (2/5)k.
Question 38
y = kx
24 = 5k
24/5 = k
12 = 10k
12/10 = k
6/5 = k
Two distinct k values tells me that the form needed is y = k/x.
I will go back to the point (5, 24).
24 = k/5
24(5) = k
120 = k
Now use (10, 12).
12 = k/10
12(10) = k
120 = k
I can stop here and assume that the needed form is y = k/x.
The model that relates x and y is y = 120/x.
You say?
36 & 38
Question 36
y = kx
2 = 5k
2/5 = k
4 = 10k
4/10 = k
2/5 = k
I will stop here and assume that the form is y = kx.
The model that relates x and y is y = (2/5)k.
Question 38
y = kx
24 = 5k
24/5 = k
12 = 10k
12/10 = k
6/5 = k
Two distinct k values tells me that the form needed is y = k/x.
I will go back to the point (5, 24).
24 = k/5
24(5) = k
120 = k
Now use (10, 12).
12 = k/10
12(10) = k
120 = k
I can stop here and assume that the needed form is y = k/x.
The model that relates x and y is y = 120/x.
You say?